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Coordinate geometry

 Angle between two lines in space Angle between two planes in space Angle between a line and a plane The angle t between two lines is the angle between two direction vectors of the lines. Take line a with direction vector u and line b with direction vector v. That is: u.v= ||u||.||v||.cos(t) and then: The angle between two planes is given by the angle between the normal vectors, n1 and n2, that is: Let's name t to the angle which line makes with plane, v the direction vector of line and n the normal vector of the plane. Then:

Choose the angle between the line $\fs2s=\{\begin{eqnarray}-5x-3y-4z&=&-9\\-6x-4y-8z&=&4\end{eqnarray}\\$ and the plane $\fs2\pi=3x-9z=4$

 -1.41 3.35 -7.65 2.01

The angle is given in degrees