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 Quadratic Equations Solve a quadratic equation using the quadratic formula The general form of a quadratic equation is where a, b, c are constants (generally integers). A quadratic equation with real coefficients can have none, one or two distinct real roots. To find them, use the Quadratic Formula: $\fs2x^2-5x+6\;=\;0\;\Rightarrow\;x=\frac{5\pm\sqrt{(-5)^2-4(1)(6)}}{2\;1}\;\Rightarrow\;x=\frac{5\pm\sqrt{25-24}}{2}\;\Rightarrow\;x=\frac{5\pm1}{2}$$\fs2x_1=\frac{5+1}{2}=\frac{6}{2}=3\;\;\;\;x_2=\frac{5-1}{2}=\frac{4}{2}=2$ Solve $\fs1-6x^2+9x-5\;=\;0$ No solution One solution x= Two solutions x1= x2=