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Nonlinear functions

Does (x,y) satisfy a nonlinear equation?

A point makes an equation true (satisfies the equation) if plugging in x and y results in a true statement.

Does (0,2) make the equation y=x2-3x+2 true?

In the ordered pair (0,2), 0 is the x-value and 2 is the y-value.
Plug x=0 and y=2 into the equation.

 y = x2-3x+2 2 $\stackrel{?}{=}$ 02-3(0)+2 2 $\stackrel{?}{=}$ 0-0+2 2 = 2

Yes, 2=2.
So, the point (0,2) satisfies the equation y=x2-3x+2

Does (0,-1) make the equation y=x2-3x true?

In the ordered pair (0,-1), 0 is the x-value and -1 is the y-value.
Plug x=0 and y=-1 into the equation.

 y = x2-3x -1 $\stackrel{?}{=}$ 02-3(0) -1 $\stackrel{?}{=}$ 0-0 -1 $\neq$ 0

No, $-1\;\neq\;0$
So, the point (0,-1) does not satisfy the equation y=x2-3x